int 1x {6 (logx) ^2+ 7logx + 2 } d x =
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Click here:point_up_2:to get an answer to your question :writing_hand:6 the value of int frac e 5 log x
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∫ dx / (x [6(logx)^2+7logx+2] ) - o1fxhx99
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∫(logx−11+(logx)2)2 is equal to
Evaluate: ∫dx/x{6(log x)^2 + 7 log x + 2} - Sarthaks eConnect
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∫1x{6(logx)2+7logx+2}dx=
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